Calculation of a force on Meca 3D

Simulation
1

Hello, I would like to ask you for your help on Solidworks and more specifically Meca 3D.

I modeled a wheelbarrow. Once on Meca 3D I have problems: my objective is to determine the effort to move the wheelbarrow forward at a speed of 1.1m/s (the conditions are a total mass of 55kg on a ground of 0° then 20°).

When making a tire connection between the wheel and the ground it does not work, how should I create this connection?

How do you determine the effort you are looking for, what are the things to do to get there? Thank you and remain at your disposal.


forum_1.png
2

Hello

Rather than using software, in this case Méca3D, it is enough to use the  kinetic energy theorem in an inclined  plane and more precisely thenon-sliding reflux on an inclined plane that allows you to have the balance of inclined plane forces.

Kind regards

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3

Okay thank you, I'll look into it as a last resort. But in my case I really have to go through the meca 3D software, so I'll keep looking. Thank you

4

Google is your friend

@+

5

Hello
I offer you some advice on the key points to process your simulation with Meca3D.
In its elementary version, your model must have 3 parts : the floor, the chassis, and the wheel.

Also 3 links :

  • - A pivot between chassis and wheel;
    - A plane support between the ground and the plane of symmetry of the chassis, in order to limit the study to a 2D dynamic;
    - A "tire" type contact between the wheel and the ground. Be sure to respect the order in which the documents are entered: tyre in n°1, floor in n°2. To enter the objects associated with the linkage, you must select the ground plane, the tire tread, and an axis (SldWks reference geometry) previously built in the wheel part, at the level of its axis of rotation. The last point is to define appropriate tyre behaviour laws, or choose a reasonable model from the database.

The model has 3 degrees of mobility :

  • - The translational displacement of the wheelbarrow defined according to Y or Z (?) of the plane support. It must be an imposed movement at a uniform speed for a first approach (1.1 m/s);
    - Tilting of the chassis in relation to the ground around a transverse axis (Z or Y of the plane support), in principle at zero speed during the movement phase of the wheelbarrow;
    - The rotation of the wheel in relation to the chassis in the pivot linkage.

External efforts : two of the mobilities are of the "imposed movement" type. It is necessary to define two unknown forces at the level of the chassis handles, forces exerted in real life by the machine manipulator:

  • - The first one, facing upwards, will be responsible for maintaining the wheelbarrow's base;
    - The second forward-facing one will be responsible for ensuring the travel speed of 1.1 m/s.

To these two efforts, it is necessary to add the actions of gravity, after having put a load in the wheelbarrow...

The calculation : it will be carried out dynamically, the first two mobilities of the "imposed movement" type, the last of the "free movement" type (it is the tire/ground contact that will control the rotation of the wheel).

Plan a small calculation step (1/1000th of a second), the "tire" link is demanding from this point of view...

Once this first model has been perfected, nothing will prevent you from making it evolve: wheelbarrow on a ground linking horizontal areas, then a 20° slope, variable speed law by curve or slider...

Do not hesitate to contact me again in case of difficulty.

M.BLT

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