Extrusion of a sheet metal

Hello
I need to extrude a cladding sheet from its neutral fiber, how would you do it?
Thank you for your help
Fred

Hello

If it's just to have the volume:

Extrusion with thin function in the middle plane.

Good luck...

4 Likes

And then otherwise, from the Sheet Metal module, you check " symmetrical " under Sheet Metal settings :wink:

4 Likes

What do you call neutral fiber? The neutral fiber depends on the thickness.
Otherwise, sketch the profile, make an extrusion and then convert to sheet metal.
That said, I don't really see the point since the positioning of the neutral fiber depends on the thickness (K factor)

3 Likes

image
This is my neutral fiber, and the thickness of my sheet metal is 1mm.

1 Like

Hello

If the bend radii are known, then it is possible to use the table below:
Inner radius x factor thickness = neutral position of the fibers

0.2 β€”β€”β€”β€”β€”β€”β€”β€”β€”β€”β€” 0.347 x thickness
0.5 β€”β€”β€”β€”β€”β€”β€”β€”β€”β€”β€” 0.387 x thickness
1 β€”β€”β€”β€”β€”β€”β€”β€”β€”β€”β€”β€” 0.421 x thickness
2 β€”β€”β€”β€”β€”β€”β€”β€”β€”β€”β€”β€” 0.451 x thickness
3 β€”β€”β€”β€”β€”β€”β€”β€”β€”β€”β€”β€” 0.465 x thickness
4 β€”β€”β€”β€”β€”β€”β€”β€”β€”β€”β€”β€” 0.470 x thickness
5 β€”β€”β€”β€”β€”β€”β€”β€”β€”β€”β€”β€” 0.478 x thickness
10 β€”β€”β€”β€”β€”β€”β€”β€”β€”β€”β€”- 0.487 x thickness

Where to use the K-Factor:

0.65>r/t<=1 k=0.3
1 k=0.35
1.5 k=0.4
2.4 k=0.45
3.8 k=0.5

If the sketch of the screenshot is indeed the " Neutral Fiber " uses the proposal of @a_eriaud and @Le_Bidule with two dimensioned extrusions (Thin Function + two directions), then transformation of the body obtained into sheet metal... Like what:
image

4 Likes

Thank you all for your answers. :+1:
Cdt
Fred

1 Like