Hello
I created this part if joined is I am looking to have the profile unfold of my part but I don't know pk the function does not my I think that knows because of the chamfer my I am not sure
s2116838.sldprt
Hello
I created this part if joined is I am looking to have the profile unfold of my part but I don't know pk the function does not my I think that knows because of the chamfer my I am not sure
Hello. I can't open because later version. But it is not possible to unfold a volume. You can unfold faces, surfaces, sheet metal but not volumes.
If you post a step there may be solutions.
Hello
You have to remove the chamfer in the flat pattern configuration and play with both configurations
Hello
1.5 or 3.5 mm? In the general sheet metal settings, the thickness is set to 3.5 mm (and the bending radius to 1 mm!).
By editing the first creation function (Folded Base Sheet1), the sheet thickness is redefined to 1.5 mm, but it seems not to have been taken into account. The value is set at 3.5 mm.
The chamfer function normally does its job, but its initial dimensions have the effect of removing the outer face of the sheet, which puts the unfolded state function in error.
If the size of the chamfer is reduced so that the outer face of the sheet is no longer removed, the unfolded state works, but the geometry of the chamfer on the unfolded shape is incorrect (angle of 60° instead of 30°?).
It seems that the sheet metal module does not support chamfers...
The solution:
- Do not use the chamfer function. After unfolding the sheet, prefer a "through-through" extrusion material removal function. Dimension the sketch in such a way as to guarantee the existence of the outer face. Fold the sheet metal...
- the final function unfolded state is then functional (see attachment, SW 2020).
One last question: what is the point of using the sheet metal features of SolidWorks to model this part?
A simple base with revolution gives geometry in a single function. And unfolding is not a problem...
Kind regards.
I just don't think about it